# Quantitative Aptitude Practice Test for SBI PO mains

QUANTITATIVE APTITUDE PRACTICE TEST
Directions(1-6): Study the following table carefully and answer these questions.
NUMBER OF CANDIDATES APPEARED AND QUALIFIED IN A COMPETITIVE EXAMINATION FROM DIFFERENT STATES OVER THE YEARS
 Year>> Sate↓ 1997 1998 1999 2000 2001 App. Qual. App. Qual. App. Qual. App. Qual. App. Qual. M 5200 720 8500 980 7400 850 6800 775 9500 1125 N 7500 840 9200 1050 8450 920 9200 980 8800 1020 P 6400 780 8800 1020 7800 890 8750 1010 9750 1250 Q 8100 950 9500 1240 8700 980 9700 1200 8950 995 R 7800 870 7600 940 9800 1350 7600 945 7990 885
1.Combining the states P and Q together in 1998, what is the percentage of the candidates qualified to that of the candidates appeared?
a)10.87%
b)11.49%
c)12.35%
d)12.54%
e)13.05%

2.The percentage of the total number of qualified candidates to the total number of appeared candidates among all the five states in 1999 is:
a)11.49%
b)11.84%
c)12.21%
d)12.57%
e)12.73%

3.What is the percentage of candidates qualified from State N for all the years together, over the candidates appeared from State N during all the years together?
a)12.36%
b)12.16%
c)11.47%
d)11.15%
e)None of these

4.What is the average of candidates who appeared from State Q during the given years?
a)8700
b)8760
c)8810
d)8920
e)8990

5.In which of the given years the number of candidates appeared from State P has maximum percentage of qualified candidates?
a)1997
b)1998
c)1999
d)2000
e)2001

6.Total number of candidates qualified from all the states together in 1997 is approximately what percentage of the total number of candidates qualified from all the states together in 1998?
a)72%
b)77%
c)80%
d)83%
e)86%

Directions(7-10): The following table gives the percentage of marks obtained by seven students in six different subjects in an examination. Study the table and answer the questions based on it.The numbers in the brackets give the maximum marks in each subject.

 Subjects(max marks)>> Student↓ Maths (150) Chemistry (130) Physics (120) Geography (100) History (60) Computer Science (40) Ayush 90 50 90 60 70 80 Aman 100 80 80 40 80 70 Sajal 90 60 70 70 90 70 Rohit 80 65 80 80 60 60 Muskan 80 65 85 95 50 90 Tanvi 70 75 65 85 40 60 Tarun 65 35 50 77 80 80
7.What was the aggregate of marks obtained by Sajal in all the six subjects?
a)409
b)419
c)429
d)439
e)449

8.What is the overall percentage of Tarun?
a)52.5%
b)55%
c)60%
d)63%
e)64.5%

9.What are the average marks obtained by all the seven students in Physics? (rounded off to two digits after decimal)
a)77.26
b)89.14
c)91.37
d)96.11
e)103.21

10.The number of students who obtained 60% and above marks in all the subjects is:
a)1
b)2
c)3
d)None
e)Can't be determined

1.c)
2.b)
3.d)
4.e)
5.e)
6.c)
7.e)
8.c)
9.b)
10.b)

Solution
1.Required% = [(1020+1240)/(8800+9500)] × 100 = (2260/18300) × 100 = 12.35%

2.Required% = [(850+920+890+980+1350)/(7400+8450+7800+8700+9800)] × 100
= (4990/42150) × 100 = 11.84%

3.Required% = [(840+1050+920+980+1020)/(7500+9200+8450+9200+8800)] × 100
= (4810/43150) × 100 = 11.15%

4.Required avg = (8100+9500+8700+9700+8950)/5 = 44950/5 = 8990

5.The percentage of candidates qualified to candidates appeared from state P during different years are:
For, 1997 = (780/6400) × 100 = 12.19%
For, 1998 = (1020/8800) × 100 = 11.59%
For, 1999 = (890/7800) × 100 = 11.41%
For, 2000 = (1010/8750) × 100 = 11.54%
For, 2001 = (1250/9750) × 100 = 12.82%
So, maximum percentage is for the year 2001.

6.Required% = [(720+840+780+950+870)/(980+1050+1020+1240+940)] × 100
= (4160/5230) × 100 = 80%(approx)

7.Aggregate marks obtained by Sajal
= [(90% of 150) + (60% of 130) + (70% of 120) + (70% of 100) + (90% of 60) + (70% of 40)]
= 135 + 78 + 84 + 70 + 54 + 28 = 449

8.Aggregate marks obtained by Tarun
= [(65% of 150) + (35% of 130) + (50% of 120) + (77% of 100) + (80% of 60) + (80% of 40)]
= 97.5 + 45.5 + 60 + 77 + 48 + 32 = 360
Total maximum marks = (150 + 130 + 120 + 100 + 60 + 40) = 600
Overall percentage of Tarun = (360/600) × 100 = 60% 9.Average marks obtained in Physics by all the seven students = 1/7 [(90% of 120) + (80% of 120) + (70% of 120) + (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120)] = 1/7 (520% of 120) = 624/7 = 89.14 10.From the table it is clear that Sajal and Rohit have 60% or more marks in each of six subjects. 