# Quantitative Aptitude Practice Test for SBI PO mains

QUANTITATIVE APTITUDE PRACTICE TEST
Directions(1-5): Study the following graph and the table and answer the given questions.
DATA OF DIFFERENT STATES REGARDING POPULATION OF STATES IN THE YEAR 1998
The total Population of the given states = 3276000

 States Sex and Literacy wise Population Ratio Sex Literacy M : F Literate : Illiterate A.P 5 : 3 2 : 7 M.P 3 : 1 1 : 4 Delhi 2 : 3 2 : 1 Goa 3 : 5 3 : 2 Bihar 3 : 4 5 : 1 U.P 3 : 2 7 : 2 T.N 3 : 4 9 : 4

1.What was the number of males in U.P in the year 1998?
a)294840
b)341200
c)254650
d)321470

2.What was the total number of illiterate people in A.P and M.P in 1998?
a)932170
b)1161160
c)876040
d)981550

3.What was the ratio of the number of females in T.N to the number of females in Delhi?
a)13 : 11
b)7 : 5
c)15 : 14
d)9 : 7

4.What will be the percentage of total number of males in U.P, M.P and Goa together to the total population of all the given states?
a)31.5%
b)25%
c)27.5%
d)28.5%

5.If in the year 1998, there was an increase of 10% in the population of U.P and 12% in the population of M.P compared to the previous year, then what was the ratio of populations of U.P and M.P in 1997?
a)4 : 5
b)7 : 11
c)48 : 55
d)42 : 55

Directions(6-10): Study the following graph carefully and answer the given questions. DISTRIBUTION OF CANDIDATES WHO WERE ENROLLED FOR MBA ENTRANCE EXAM AND THE CANDIDATES (OUT OF THOSE ENROLLED) WHO PASSED THE EXAM IN DIFFERENT INSTITUTES.

6.What percentage of candidates passed the Exam from institute T out of the total number of candidates enrolled from the same institute?
a)50%
b)62.5%
c)75%
d)80%

7.What is the ratio of candidates passed to the candidates enrolled from institute P?
a)9 : 11
b)14 : 17
c)6 : 11
d)9 : 17

8.What is the percentage of candidates passed to the candidates enrolled for institutes Q and R together?
a)68%
b)80%
c)74%
d)65%

9.Which institute has the highest percentage of candidates passed to the candidates enrolled?
a)Q
b)R
c)V
d)T

10.The number of candidates passed from institutes S and P together exceeds the number of candidates enrolled from institutes T and R together by:
a)228
b)279
c)399
d)407

1.a)
2.b)
3.c)
4.d)
5.d)
6.c)
7.c)
8.b)
9.b)
10.c)

Solution
1.Number of males in U.P = [3/5 of (15% of 3276000)] = [3/5 of (15/100 of 3276000)] = 294840

2.No. of illiterate people in A.P = [7/9 of (25% of 3276000)] = 637000
No. of illiterate people in M.P = [4/5 of (20% of 3276000)] = 524160
Total number = (637000 + 524160) = 1161160

3.Required ratio = [4/5 of (9% of 3276000) : [3/5 of (8% of 3276000)]
= (4/7 × 9) : (3/5 × 8) = 15 : 14

4.Number of males in U.P = [3/5 of (15% of N)] = 3/5 × 15/100 × N = 9 × N/100 [N = 3276000] Number of males in M.P = [3/4 of (20% of N)] = 3/4 × 20/100 × N = 15 × N/100
Number of males in Goa = [3/8 of (12% of N)] = 3/8 × 12/100 × N = 4.5 × N/100
so, total number of males in these three states = (9+15+4.5) × N/100 = 28.5 × N/100
Required% = [(28.5 × N/100)/N] × 100 = 28.5%

5.Let x be the population of U.P in 1997.
Then, Population of U.P in 1998 = 110% of x = 110x/100
Also, let y be the population of M.P in 1997.
Then, Population of M.P in 1998 = 112% of y = 112y/100
Ratio of populations of U.P and M.P in 1998 = (110x/100) : (112y/100) = 110x : 112y
From the pie-chart, this ratio is 15/20
so, 110x/112y = 15/20
or, x/y = 15/20 × 112/100 = 42/55
Thus, ratio of populations of U.P and M.P in 1997 = 42 : 55

6.Required% = [(9% of 5700)/(8% of 8550)] × 100 = 75%

7.Required ratio = (18% of 5700) : (22% of 8550) = 6 : 11

8.Candidates passed from institutes Q and R together = [(13% + 17%) of 5700] = 30% Of 5700 Candidates enrolled from institutes Q and R together = [(15% + 10%) 0f 8550] = 25% Of 8550
so, required% = [(30% of 5700)/(25% of 8550)] × 100 = 80%

9.The percentage of candidates passed to candidates enrolled can be determined for each institute as under:
P = [(18% of 5700)/(22% of 8550)] × 100 = 54.55%
Q = [(17% of 5700)/(15% of 8550)] × 100 = 75.56%
R = [(13% of 5700)/(10% of 8550)] × 100 = 86.67%
S = [(16% of 5700)/(17% of 8550)] × 100 = 62.75%
T = [(9% of 5700)/(8% of 8550)] × 100 = 75%
V = [(15% of 5700)/(12% of 8550)] × 100 = 83.33%
X = [(12% of 5700)/(16% of 8550)] × 100 = 50%
Highest of these is 86.67% corresponding to institute R.

10.Required difference = [(16% + 18%) of 5700]   ̶  [(8% + 10%) of 8550]
= (1938   ̶  1539) = 399 