Quantitative Aptitude Practice Test for SBI PO mains

QUANTITATIVE APTITUDE PRACTICE TEST

Directions(1-5): The following table gives the sales of batteries manufactured by a company over the years. Study the table and answer the questions given below.
Number of different types of batteries sold by a company over the years (numbers in thousands)

BATTERY>> YEAR↓	4AH	7AH	32AH	35AH	55AH	TOTAL
1992	75	144	114	102	108	543
1993	90	126	102	84	126	528
1994	96	114	75	105	135	525
1995	105	90	150	90	75	510
1996	90	75	135	75	90	465
1997	105	60	165	45	120	495
1998	115	85	160	100	145	605

1.The total sales of all the seven years is the maximum for which battery?
a)4AH
b)7AH
c)32AH
d)35AH
e)55AH

2.What is the difference in the number of 35AH batteries sold in 1993 and 1997?
a)24000
b)28000
c)35000
d)39000
e)42000

3.The percentage of 4AH batteries sold to the total number of batteries sold was maximum in the year:
a)1994
b)1995
c)1996
d)1997
e)1998

4.In the case of which battery there was a continuous decrease in sales from 1992 to 1997?
a)4AH
b)7AH
c)32AH
d)35AH
e)55AH

5.What was the approximate percentage increase in the sales of 55AH batteries in 1998 compared to that in 1992?
a)28%
b)31%
c)33%
d)34%
e)37%

Directions(6-10): Study the following pie-chart and the table and answer the questions.        
PROPORTION OF POPULATION OF SEVEN VILLAGES IN 1997

Village	% Population below poverty line
X	38
Y	52
Z	42
R	51
S	49
T	46
V	58

6.Find the population of village S if the population of village X below poverty line in 1997 is 12160.
a)18500
b)20500
c)22000
d)26000

7.The ratio of population of village T below poverty line to that of village Z below poverty line in 1997 is:
a)11:23
b)13:11
c)23:11
d)11:13

8.If the population of village R in 1997 is 32000, then what will be the population of village Y below poverty line in that year?
a)14100
b)15600
c)16500
d)17000

9.If in 1998, the population of villages Y and V increase by 10% each and the percentage of population below poverty line remains unchanged for all the villages, then find the population of village V below poverty line in 1998, given that the population of village Y in 1997 was 30000. a)11250
b)12760
c)13140
d)13780

10.If in 1999, the population of village R increases by 10% while that of village Z reduces by 5% compared to that in 1997 and the percentage of population below poverty line remains unchanged for all the villages, then find the approximate ratio of population of village R below poverty line to the ratio of population of village Z below poverty line for the year 1999.
a)2:1
b)3:2
c)4:3
d)5:4

Answer key

1.c)
2.d)
3.d)
4.b)
5.d)
6.c)
7.c)
8.b)
9.b)
10.a)

Solution

1.The total sales (in thousands) of all the seven years for various batteries are:
   For, 4AH = 75 + 90 + 96 + 105 + 90 + 105 + 115 = 676
   For, 7AH = 144 + 126 + 114 + 90 + 75 + 60 + 85 = 694
   For, 32AH = 114 + 102 + 75 + 150 + 135 + 165 + 160 = 901
   For, 35AH = 102 + 84 + 105 + 90 + 75 + 45 + 100 = 601
   For, 55AH = 108 + 126 + 135 + 75 + 90 + 120 + 145 = 799
  clearly, sales are maximum in case of 32AH batteries.

2.Required difference = [(84  ̶  45) × 1000] = 39000

3.For, 1992 = (75/543) × 100 = 13.81%
   For, 1993 = (90/528) × 100 = 17.05%
   For, 1994 = (96/525) × 100 = 18.29%
   For, 1995 = (105/510) × 100 = 20.59%
   For, 1996 = (96/465) × 100 = 19.35%
   For, 1997 = (105/495) × 100 = 21.21%
   For, 1998 = (115/605) × 100 = 19.01%

4.From the table it is clear that the sales of 7AH batteries have been decreasing continuously from 1992 to 1997.

5.Required % = [(145  ̶  108) / 108] × 100 = 34.26% ≈ 34%

6.Let the population of village X be x.
   Then, 38% of x = 12160
                    Or, x = (12160 × 100)/38 = 32000
   Now, if s be the population of village S,
   then 16 : 11 = 32000 : s
         Or, s = ( 11 × 32000)/16 = 22000

7.let N be the total population of all the seven villages.
Then, population of village T below poverty line = 46% of (21% of N) and
population of village Z below poverty line = 42% of (11% of N)
so, required ratio = 46% of (21% of N) : 42% of (11% of N)
                            = (46 × 21) : (42 × 11)
                            = 23 : 11

8.Population of village R = 32000 (given)
Let the population of village Y be y.
Then, 16 : 15 = 32000 : y
Or, y = (15 × 32000)/16 = 30000
So, population of village Y below poverty line = 52% of 30000 = 15600

9.Population of village Y in 1997 = 30000 (given)
Let the population of village V be v.
Then, 15 : 10 = 30000 : v
Or, v = (10 × 30000)/15 = 20000
Now, population of village V in 1998 = 20000 + (10% of 20000) = 22000
So, population of village V below poverty line in 1998 = 58% of 22000 = 12760

10.Let the total population of all the seven villages in 1997 be N.
Then, population of village R in 1997 = 16% of N = 16N/100 and
Population of village Z in 1997 = 11% of N = 11N/100.
So, population of village R in 1999 = [(16N/100) + {10% of (16N/100)}] = 1760N/10000 And population of village Z in 1999 = [(11N/100)  ̶  {5% of (11N/100)}] = 1045N/10000
Now, population of village R below poverty line for 1999 = 51% of (1760N/10000) And
population of village Z below poverty line for 1999 = 42% of (1045N/10000)
So, required ratio = 51% of (1760N/10000) : 42% of (1045N/10000)
                             ≈ 2 : 1