QUANTITATIVE APTITUDE PRACTICE TEST
Directions(15): Study the following Graph and Table carefully and answer the questions given below it.Percentage of Males, Females and Children living in various colonies
Total number of Residents in various colonies
Colonies

Residents

A

1250

B

2050

C

1800

D

1150

E

1620

1.What is the total number of females in colonies A, B and C together?
a)1785
b)1821
c)1479
d)1692
e)None of these
2.The number of Children in colony A are approximately what percent of the number of children in colony E?
a)121%
b)116%
c)75%
d)101%
e)98%
3.What is the respective ratio of the number of males in colony B to the number of females in the same colony?
a)3:5
b)7:5
c)8:7
d)5:7
e)None of these
4.What is the average number of residents from all the colonies together?
a)1654
b)1600
c)1580
d)1574
e)None of these
5.What is the difference between the number of males in colony D and the number of children in the same colony?
a)138
b)126
c)136
d)135
e)None of these
Directions(610): Study the following table carefully and answer the questions given below it.
Number of Entertainment Shows held in various cities in a year (Number in Hundreds)
Cities

Shows


Dance

Music

Drama

Stand up Comedy

Mimicry


M

15

21

24

0.8

0.9

N

12.4

13

26

2

0.5

O

5.7

8

12

0.3

0.2

P

11.3

6

18

1

1.5

Q

17

12.4

11

3

0.4

R

14

10.5

9.8

0.7

0.1

6.The mimicry shows held in city M are what percent of the drama shows held in city O ?
a)7%
b)8.5%
c)6.5%
d)8%
e)None of these
7.What is the average number of entertainment shows held in city P?
a)756
b)678
c)786
d)698
e)None of these
8.If the number of music shows in cities N and Q is increased by 5%, what will be the total number of music shows in both the cities together?
a)2602
b)2667
c)2540
d)2605
e)None of these
9.What is the respective ratio of the number of dance shows held in city N to the number of drama shows held in city R?
a)49:62
b)49:51
c)62:45
d)62:49
e)None of these
10.What is the total number of stand up comedy shows held in all the cities together?
a)820
b)740
c)780
d)810
e)None of these
Answer key
2.b)
3.e)
4.d)
5.a)
6.e)
7.a)
8.b)
9.d)
10.c)
Solution
= (1250×36)/100 + (2050×30)/100 + (1800×42)/100
= 450 + 615 + 756
= 1821
2.No. of children in colony A = (1250 × 30)/100 = 375
No. of children in colony E = (1620 × 20)/100 = 324
Required% = (375/324) × 100 = 116% (approx)
3.Required ratio = 50 : 30 = 5 : 3
4.Average number of residents from all the colonies together
= (1250 + 2050 + 1800 + 1150 + 1620)/5
= 1574
5.Required difference = (38  26)% of 1150 = 138
6.Required% = (0.9/12) × 100 = 7.5%
7.Required average
= (11.3 + 6 + 18 + 1 + 1.5)/5 × 100
= 756
8.No. of music shows in cities N and Q
= 15% of (13 + 12.4) × 100
= 2667
9.Required ratio = 12.4 : 9.8 = 124 : 98 = 62 : 49
10.Total number of stand up comedy shows
= (0.8 + 2 + 0.3 + 1 + 3 + 0.7) × 100
= 780
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